A boy pushes the wall in the class for five m | vedclass

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Question

(B) Work is defined as the product of force and displacement in the direction of the force $(W = F 	imes s)$.In the first case,the boy pushes the wal

Vedclass · Accepted Answer

Work done on the chair is more.

Vedclass · Answer

(B) Work is defined as the product of force and displacement in the direction of the force $(W = F 	imes s)$.In the first case,the boy pushes the wall,but since the wall does not move,the displacement $(s)$ is $0$. Therefore,the work done on the wall is $W = F 	imes 0 = 0$.In the second case,the boy pushes the chair,and it moves from the front to the back of the class,meaning there is a non-zero displacement $(s > 0)$.Since work is done on the chair and zero work is done on the wall,more work is done in the case of the chair.

$A$ boy pushes the wall in the class for five minutes but the wall does not move. Another boy pushes the chair from the front to the back side of the class. In which case,more work is done?

Similar Questions

List two conditions which need to be satisfied for the work to be done on an object.

The work done by a force on a body will be positive if the:

$(a)$ How much work is done when a force of $1\, N$ moves a body through a distance of $1\, m$ in its direction?
$(b)$ Is it possible that a force is acting on a body but still the work done is zero? Explain giving one example.

Define work. How is work measured? When is work done by a force negative?

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